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integral of (N^2 * pdf)

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∫ [ N^2 * pdf(N) ] dN = ?

I'm deriving equations, and I'm stuck at the following.

+inf
∫ [ N^2 * pdf(N) ] dN = ?
-inf

where N: random variable,pdf: Gaussian probability distribution function.

Can we express the above equation without pdf(N) or whatever we can derive?

Thanks,
 
Last edited:

Hi talking,

If I understand your post, you are asking for the second moment of a Gaussian distribution (of zero mean).
It is sigma^2.
Regards

Z
 
Thank you so much for help, Zorro. You answer accelerated my research!!!
 

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