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Replace a 8:1 MUX with 4:1 's

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makis89

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Hello everyone, i would be glad if you could help me with my question. I have this boolean equation: F= BC'D' + ACD' , and i want to realise it with 4:1 Multiplexers. I have managed to realise it with one 8:1 multiplexer by using the signals D,C and B as selectors and 1,0 and A as inputs but i cannot figure out how to do it with 4:1's, since a 4:1 MUX can realise an equation of 3 inputs.

Can you give me any tips ? I don't ask for the solution itself, just a tip that could help me, such as how should i divide the signals to the MUXes etc.

Thanks a lot.

Regards,
Makis
 

you can build a 8:1 mux by using 3 4:1 muxes.

23_1200898502.jpg


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Thank you, i wil try it out...
 

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