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solve the following DSP program

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srinivas.nrt

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Assume the data memory starts at 1400h and program memory starts at 1000h

.memregs
.data
a0 .word 1234h
b0 .word 2345h
c0 .word 3456h
d0 .word 4567h
e0 .word 5678h

.text
ld #40,dp
ld #1Ch,asm
ld a0,t
mpyR 2,a
sth a,asm,6
.end

(a) what will be the content of accumulator after execution of instruction mpyR 2,a
in hexadecimal format.
(b) At which memory location the final result will be stored after execution of instruction sth a,asm,6
(c)What will be the final result that will be stored in the destination memory location after execution of instruction sth a,asm,6
 

srinivas.nrt said:
Assume the data memory starts at 1400h and program memory starts at 1000h

.memregs
.data
a0 .word 1234h
b0 .word 2345h
c0 .word 3456h
d0 .word 4567h
e0 .word 5678h

.text
ld #40,dp
ld #1Ch,asm
ld a0,t
mpyR 2,a
sth a,asm,6
.end

(a) what will be the content of accumulator after execution of instruction mpyR 2,a
in hexadecimal format.
(b) At which memory location the final result will be stored after execution of instruction sth a,asm,6
(c)What will be the final result that will be stored in the destination memory location after execution of instruction sth a,asm,6
Click to expand...
hay it is not executing properly
 
sundarmeenakshi said:
srinivas.nrt said:
Assume the data memory starts at 1400h and program memory starts at 1000h

.memregs
.data
a0 .word 1234h
b0 .word 2345h
c0 .word 3456h
d0 .word 4567h
e0 .word 5678h

.text
ld #40,dp
ld #1Ch,asm
ld a0,t
mpyR 2,a
sth a,asm,6
.end

(a) what will be the content of accumulator after execution of instruction mpyR 2,a
in hexadecimal format.
(b) At which memory location the final result will be stored after execution of instruction sth a,asm,6
(c)What will be the final result that will be stored in the destination memory location after execution of instruction sth a,asm,6
Click to expand...
hay it is not executing properly
Click to expand...

where was the problem sir. i couldnt understood
 

srinivas.nrt said:
sundarmeenakshi said:
srinivas.nrt said:
Assume the data memory starts at 1400h and program memory starts at 1000h

.memregs
.data
a0 .word 1234h
b0 .word 2345h
c0 .word 3456h
d0 .word 4567h
e0 .word 5678h

.text
ld #40,dp
ld #1Ch,asm
ld a0,t
mpyR 2,a
sth a,asm,6
.end

(a) what will be the content of accumulator after execution of instruction mpyR 2,a
in hexadecimal format.
(b) At which memory location the final result will be stored after execution of instruction sth a,asm,6
(c)What will be the final result that will be stored in the destination memory location after execution of instruction sth a,asm,6
Click to expand...
hay it is not executing properly
Click to expand...

where was the problem sir. i couldnt understood
Click to expand...
it is again assingin the value for PC
 
sundarmeenakshi said:
srinivas.nrt said:
sundarmeenakshi said:
srinivas.nrt said:
Assume the data memory starts at 1400h and program memory starts at 1000h

.memregs
.data
a0 .word 1234h
b0 .word 2345h
c0 .word 3456h
d0 .word 4567h
e0 .word 5678h

.text
ld #40,dp
ld #1Ch,asm
ld a0,t
mpyR 2,a
sth a,asm,6
.end

(a) what will be the content of accumulator after execution of instruction mpyR 2,a
in hexadecimal format.
(b) At which memory location the final result will be stored after execution of instruction sth a,asm,6
(c)What will be the final result that will be stored in the destination memory location after execution of instruction sth a,asm,6
Click to expand...
hay it is not executing properly
Click to expand...

where was the problem sir. i couldnt understood
Click to expand...
it is again assingin the value for PC
Click to expand...

In which statement it is assigning sir
 

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