BlackOps
Full Member level 5
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I am very confused with very simple thing...
i have developed simple problem, for example on the pic u see the graph of the Current which was applied to the capacitor... now i must know how will the Voltage graph look like...
Capacitor = 3µF
so:
v(t) = 1/C * (∫t0-t i(t')dt') + v0
the graph of I(t) on the interval from 0mS to 3mS is x^2, is parabola.
i can say that the V-t graph on interval from 3mS to 6mS will look like on picture... it will be straignt line. because: V(t) = 1/C * area of the rectangle ===> V(t) = (1/3 * 10^-6) * 3 * 10^-3 * 9 * 10^-3 = 9V...
but i am confused about how will look the graph on V-t from 0mS to 3mS interval...
and please derive the step by step integral equation for computing the expression from 0 to 3 ms
thanks, sometimes simple things make me confused![Smile :) :)](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
i will be very gratefull if u sketch correct graph and upload it here...
i have developed simple problem, for example on the pic u see the graph of the Current which was applied to the capacitor... now i must know how will the Voltage graph look like...
Capacitor = 3µF
so:
v(t) = 1/C * (∫t0-t i(t')dt') + v0
the graph of I(t) on the interval from 0mS to 3mS is x^2, is parabola.
i can say that the V-t graph on interval from 3mS to 6mS will look like on picture... it will be straignt line. because: V(t) = 1/C * area of the rectangle ===> V(t) = (1/3 * 10^-6) * 3 * 10^-3 * 9 * 10^-3 = 9V...
but i am confused about how will look the graph on V-t from 0mS to 3mS interval...
and please derive the step by step integral equation for computing the expression from 0 to 3 ms
thanks, sometimes simple things make me confused
i will be very gratefull if u sketch correct graph and upload it here...