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Problem with the curvature of a bandgap from Razavi's book

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Usman Hai

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Hi, I am simulating the bandgap given in Razavi book as shown in figure. I am using TSMC 0.18um tech.
66_1175702663.jpg


The problem is I am not getting the curvature as indicated in the book and othr books. I am getting linear downward slope, yes of less than 1mV, but I need the curvature when sweeping the temperature from 0C till 100C. Is it because of 0.18um tech or what?
Can you tell me what device sizes I should use for Bipolar areas and what should be the temperature coefficients of real resistors on chip. Any suggestion or hint will be extremely useful.
I heard also that it might be simulator error, but I need to confirm so any opinion on this will be highly appreciated as well.
Thanks in advance[/img]
 

Re: bandgap question

Two steps for you to do:

1) In you bandgap circuit, zero TC point is negative temperature. Try to sweep your tempareture range from -100C to 100C, you may the desired curve. I think this is mainly because your opamp offset voltage and resistor ratio (R3+R2)/R3 shift the curver to left.

2) Since you are getting downward slope which means negative TC, what you should do is to increase the resistor ratio (R3+R2)/R3 to move zero TC point to your desired tempareture.

When you really fabricate a bandgap, you need to add more dummy resistors and resistor taps in your layout for future trimming and metal mask change.
 

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    Usman Hai

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Re: bandgap question

You have your Zero TC point in a negative temperature, you have to move it to a positive temperature.

It's more important to choose the ratio between the two areas than the area of each bjt, because you could achieve a better matching. For achieving a better matching use COMMON-CENTROID LAYOUT. The ratio could be 8, 24, 48, etc.

The temperature coefficients of real resistors on chip depend of the resistors material, I suggest you use high-resistive polysilicon (1.2kohm/square), TC=-0.0004/K
 

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    Usman Hai

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