question about the capacitor in a clamping circuit..

What is the effect of shorting out the capacitor in a clamping circuit?

Hi...........I give you two reasons out of which you need to choose dependent on the circuit since you have not given any circuit...........

Reason 1:::::The impedance of a capacitor is inversely proportional to the frequency -- that is, for very high-frequency alternating currents the reactance approaches zero -- so that a capacitor is nearly a short circuit to a very high frequency AC source. Conversely, for very low frequency alternating currents, the reactance increases without bound so that a capacitor is nearly an open circuit to a very low frequency AC source. This frequency dependent behaviour accounts for most uses of the capacitor


Reason 2:::::For safety purposes, all large capacitors should be discharged before handling. For board-level capacitors, this is done by placing a bleeder resistor across the terminals, whose resistance is large enough that the leakage current will not affect the circuit, but small enough to discharge the capacitor shortly after power is removed. High-voltage capacitors should be stored with the terminals shorted, since temporarily discharged capacitors can develop potentially dangerous voltages when the terminals are left open-circuited.



Good luck...............

i'm assuming by clamping circuit you use a diode and a cap to clamp the voltage., shoring the cap i believe would cause it to become a 1/4 wave rectifier.