ahmed_nasr
Member level 3
i wanna know how does the transistor convert the DC power of the amplifier circuit to amplify the ac signal ? in case of BJT for example ?
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ahmed_nasr said:i wanna know how does the transistor converts the DC power of the amplifier circuit to amplify the ac signal ? in case of BJT for example ?
i wanna know how does the transistor converts the DC power of the amplifier circuit to amplify the ac signal ? in case of BJT for example ?
BJTs are current controlled devices, the base current controls the collector current flow.
well, I will try to explain with the example.
.... small power applied by you on the small valve is converted to higher power by the big valve using the water stored in the tank.. thats amplification
i hope you understand it....
Actually what the transistors(BJT, etc, not CMOS) amplified is the current changed in the base, a little change in base current result in a large change in collector current, Am I right?
Hence, a transistor does not amplify a signal; rather, it only allows you to try to copy it by a scale factor that you'd like to be linear but never is.
with the help of DC supply,it amplify the small ac signal to large signal.because transistor has low i/p resistance(F.B) and large o/p impedance(R.B). .
....
...and this is all about how the input signal is amplified.
according to practical base ,
when comes the input signal (having to amplify) at the base of then the transistor passes the dc signal (connected through emittor and collector ) may vary (reversly ,means 180 degree) in accordance with the input signal .
please go though all the threads and pls some one links all the patches and enlighten us.
transisitors are infact transfere resistors. You could change the resistance by the base (or gate ) signals. if you change the resistance of a resistor coonected to a dc voltage supply with the help of gate signal ; an exact replica of the gate signal with higher amplitute will be produced.
thanks for u all .... actually i understand all that ..... i was asking for the physical explanatio for it coz i read it many times in many books but couldnt get it ..... but it seems its not only me ....
or physical significance you can take analogy of transistor as a tube of water flowing in it, and and the input signal is like a you pressing the tube and as you vary the pressure on the tube the pressure of water coming out varies, the larger the pressure on tube larger is pressure of water,
power supply is analogous to incoming pressure and input resistance is analogous to the diameter of the tube larger the diameter less is opposition to water.
power supply is analogous to incoming pressure and input resistance is analogous to the diameter of the tube larger the diameter less is opposition to water.
note in a BJT beam electron is flowing from Emitter to Collector and a pressure(voltage) is applied at base that controls the current in the emitter.
note if you press the tube very hard then a situation comes when no more water is allowed that is analogous to saturation of transistor
Almost every signal source is a fairly high resistance current source. The collector of a previous transistor stage has the resistance of its collector resistor.I think, the shown characteristics are well-known.
The distortions you call "severe" are kept within limits by using an appropriate bias point - together with signal feedback.
"If the input to the base is a high impedance current change then the output voltage and current changes are very linear."
So - what do you propose? Not to use anymore all the classical voltage-in transistor amplifier stages in C-E configuration?
Should we convert all signal voltages into signal currents before feeding the amplifier?