kumar_eee
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Why silicon takes 0.7v & Germanium 0.3v for biasing?...
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for a diode to conduct current ,applied force(volt) should dominate the barrier potential( potential of depletion region--it's own potential formed due to coupling of two elements p and n)for si, barrier potential is .7 and for Ge it is .3v...so for current flow across the respective elements,applied volt must cross .7 or .3....kumar_eee said:Why silicon takes 0.7v & Germanium 0.3v for biasing?...
electronics_kumar said:for a diode to conduct current ,applied force(volt) should dominate the barrier potential( potential of depletion region--it's own potential formed due to coupling of two elements p and n)for si, barrier potential is .7 and for Ge it is .3v...so for current flow across the respective elements,applied volt must cross .7 or .3....kumar_eee said:Why silicon takes 0.7v & Germanium 0.3v for biasing?...
A Schottky diode uses a metal-semiconductor junction as a Schottky barrier (instead of a semiconductor-semiconductor junction as in conventional diodes).
Muhammad Raza said:.
basically barrier potential indicates the number of holes and electronics combined.
RAZA