haydar
Advanced Member level 4
Hi
I need to find the expression: (Hρ-jHφ)/√2
this is right hand circularly polarized H field(H+). I did not find how to do that in hfss.
can anybody help?thanks.
I need to find the expression: (Hρ-jHφ)/√2
this is right hand circularly polarized H field(H+). I did not find how to do that in hfss.
can anybody help?thanks.