carl5
Junior Member level 1
Hi,
From calculations, for a perfect pure resistance have same value of D.C. resistance and A.C. resistance(impedance).
So for same value of D.C. value of voltage and rms value of A.C. voltage, the current must be same for this case.
Q1) Do above sentence are right?
Q2) For impedance, Z=√[(r²)+(x²)] must be greater than the dc resistance(for steady state condition). Below video says that for same amount of voltage of A.C. and D.C. the A.C. current is higher!!! Which means impedance is lower than resistance!!
At 3:33, the current corresponding to the 20V A.C. is 7mA. While at 4:36, the current corresponding to the 20V D.C. is 5.6mA.
How this happened?
Thanks for making me understand in advance.
From calculations, for a perfect pure resistance have same value of D.C. resistance and A.C. resistance(impedance).
So for same value of D.C. value of voltage and rms value of A.C. voltage, the current must be same for this case.
Q1) Do above sentence are right?
Q2) For impedance, Z=√[(r²)+(x²)] must be greater than the dc resistance(for steady state condition). Below video says that for same amount of voltage of A.C. and D.C. the A.C. current is higher!!! Which means impedance is lower than resistance!!
At 3:33, the current corresponding to the 20V A.C. is 7mA. While at 4:36, the current corresponding to the 20V D.C. is 5.6mA.
How this happened?
Thanks for making me understand in advance.