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Usb port component fried

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J

Javid.zare.s

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Newbie level 1
Hi
My pc's usb port is damaged . Two out of four ports where damaged before and now the other two
I looked inside and found out same component behind both ports is burned.
Heres a picture:

Theres no code or number on component ,any ideas?
Ps. Ps they are not like components next to them
 

Hi,

They could be Zener diodes, TVS, maybe resistors or even capacitors.

Maybe reading these could be of help:

**broken link removed**

I searched for this: usb pinout d+ and d- with diodes. These are the results.
 

    V

    Points: 2
    Helpful Answer Positive Rating
d123 said:
Hi,

They could be Zener diodes, TVS, maybe resistors or even capacitors.

Maybe reading these could be of help:

**broken link removed**

I searched for this: usb pinout d+ and d- with diodes. These are the results.
Click to expand...
Thks man , i tested resistance of them , one of them showed around 1.5kohm (not a diode)
Another one just nothing zero ohms,
The question is can i just put another 1.5k resistor or random capacitor/diode there to see if it works or not?
Can this harm the mainboard?
 

Hi,

Personally, I would not replace the two burnt parts with random components, it could harm other parts of the mainboard or just do nothing of use. One approach would be to desolder those two parts from the board and then do continuity and resistance tests. Another, more time-consuming, would be to try to locate the board's reference number/name, then see if you can find a schematic online somewhere, or a link to a PC repair web where it is discussed, and see if any concrete information comes up about those two parts before doing anything regrettable.

Sometimes measuring resistance on a pcb can be misleading, so perhaps it's best be a little wary of them being 0 ohms and 1K5, even if those turn out to be the real values.

I'd search around a bit for the mainboard part number. Also, it looks unlikely 'though, maybe cleaning the top of those components with a cotton wool bud (and if necessary e.g. 96% alcohol) might help to show what's left of any markings - best to get them off the board first if possible.

Not sure what else I could suggest.

Any idea as to what caused this to happen each time? Is the board very old? Did you connect something with a different wiring where data and power, or power and ground were reversed? It would be interesting to know what causes that to happen.
 

    V

    Points: 2
    Helpful Answer Positive Rating
The burnt out component next to the other zero ohm resistors is probably another zero ohm resistor, these are often used as fuses, the other burnt out component is probably a fuse. Try putting a link across them you have little to lose.
 

    V

    Points: 2
    Helpful Answer Positive Rating
d123 said:
Hi,

Personally, I would not replace the two burnt parts with random components, it could harm other parts of the mainboard or just do nothing of use. One approach would be to desolder those two parts from the board and then do continuity and resistance tests. Another, more time-consuming, would be to try to locate the board's reference number/name, then see if you can find a schematic online somewhere, or a link to a PC repair web where it is discussed, and see if any concrete information comes up about those two parts before doing anything regrettable.

Sometimes measuring resistance on a pcb can be misleading, so perhaps it's best be a little wary of them being 0 ohms and 1K5, even if those turn out to be the real values.

I'd search around a bit for the mainboard part number. Also, it looks unlikely 'though, maybe cleaning the top of those components with a cotton wool bud (and if necessary e.g. 96% alcohol) might help to show what's left of any markings - best to get them off the board first if possible.

Not sure what else I could suggest.

Any idea as to what caused this to happen each time? Is the board very old? Did you connect something with a different wiring where data and power, or power and ground were reversed? It would be interesting to know what causes that to happen.
Click to expand...

First thank you for the time you spend for explaination..��������
I cleaned with alcohol but nothing is shown up
The ports are exactly looking same but i say one is for lower usb port
which totaly lost power another one is for upper usb ports which can deliver very low amount of current that can shake my usb gamepad vibrator motor (slow shaking)
I think they blow up cause my ipad cable caused shortcircuit
How can i realize they are resistors ? Cause my multimeter doesnt show a stable number ,resistance starts with for example 100 kohms then slowly comes to 1k5 which isnt normal for my multimeter
Can this damaged resistor(if it is a resistor) still deliver current?or lets say is it still capble of?

- - - Updated - - -

pjmelect said:
The burnt out component next to the other zero ohm resistors is probably another zero ohm resistor, these are often used as fuses, the other burnt out component is probably a fuse. Try putting a link across them you have little to lose.
Click to expand...

But the component has more thickness than 0ohm resistors
In the worst senario ,What do you thick will happen if i just deny part and put a 0ohm resistor in those places?
Can i do something to do this test in a controlled enviroment so i dont explode anything more in mainboard?!
 

Hi,

Have you looked through pictures of various SMD diodes? I can't see from the photo if the two burnt components have pins at the bottom, but from the top they look quite a lot like diodes (if the grey strip was grey before they got burnt and the other end didn't have the same marking). Which doesn't mean they are not, as suggested, 0 Ohm resistors. Out of curiosity - I don't have any burnt resistors to hand - I just measured a 1N4007 diode on the DMM ohmmeter setting, and it either read O.L. or with the connection reversed the value rose slowly; I also tried with a 10nF capacitor (in the unlikely event of yours being polymer capactors) but that just read O.L. so I do not know why that happens when you measure them.

If you measured the resistance with them still soldered to the board you can expect odd things to happen with the readings - if you can, which may be too difficult for whatever reasons, you should remove them (they are burnt, after all) and then measure them.

Another thing with mainboards, like when cleaning the fan: disconnect mains lead (and remove battery if a laptop), then press the on button a few times to discharge the capacitors before doing anything.

I don't know what to say, as I can appreciate it not being appealing just trying random things out. If you can't get hold of a description of the mainboard from its part number, ask around on PC repair forums. It's common sense.
 

    V

    Points: 2
    Helpful Answer Positive Rating
You must remember that the highest voltage on a USB port is only 5V to have enough power to burn out those devices would require them to be of low resistance or a diode. For example a 1.5K resistor cannot burn out unless you fed a high voltage back into the USB port. For a resistor to burn out it would have to be less than 30 ohms or so. I would try and replace the burnt out components one at a time with fuse wire rated at a few hundred mA and see what happens.
 

d123 said:
Hi,

Have you looked through pictures of various SMD diodes? I can't see from the photo if the two burnt components have pins at the bottom, but from the top they look quite a lot like diodes (if the grey strip was grey before they got burnt and the other end didn't have the same marking). Which doesn't mean they are not, as suggested, 0 Ohm resistors. Out of curiosity - I don't have any burnt resistors to hand - I just measured a 1N4007 diode on the DMM ohmmeter setting, and it either read O.L. or with the connection reversed the value rose slowly; I also tried with a 10nF capacitor (in the unlikely event of yours being polymer capactors) but that just read O.L. so I do not know why that happens when you measure them.

If you measured the resistance with them still soldered to the board you can expect odd things to happen with the readings - if you can, which may be too difficult for whatever reasons, you should remove them (they are burnt, after all) and then measure them.

Another thing with mainboards, like when cleaning the fan: disconnect mains lead (and remove battery if a laptop), then press the on button a few times to discharge the capacitors before doing anything.

I don't know what to say, as I can appreciate it not being appealing just trying random things out. If you can't get hold of a description of the mainboard from its part number, ask around on PC repair forums. It's common sense.
Click to expand...

Yea my mainboard is pretty old and i am sure its even older than lot of members in pc forums ��
i just desoldered the parts and one still says 1k5 another doesnt show stable number but most of the time below 50 ohm
diode tester of multimeter confirms that its not a capacitor and due to beeps on both sides they are not a diode either
So
I should look for a replacment with 1k5 ohm or lower?
New pic:


- - - Updated - - -

d123 said:
Hi,

Have you looked through pictures of various SMD diodes? I can't see from the photo if the two burnt components have pins at the bottom, but from the top they look quite a lot like diodes (if the grey strip was grey before they got burnt and the other end didn't have the same marking). Which doesn't mean they are not, as suggested, 0 Ohm resistors. Out of curiosity - I don't have any burnt resistors to hand - I just measured a 1N4007 diode on the DMM ohmmeter setting, and it either read O.L. or with the connection reversed the value rose slowly; I also tried with a 10nF capacitor (in the unlikely event of yours being polymer capactors) but that just read O.L. so I do not know why that happens when you measure them.

If you measured the resistance with them still soldered to the board you can expect odd things to happen with the readings - if you can, which may be too difficult for whatever reasons, you should remove them (they are burnt, after all) and then measure them.

Another thing with mainboards, like when cleaning the fan: disconnect mains lead (and remove battery if a laptop), then press the on button a few times to discharge the capacitors before doing anything.

I don't know what to say, as I can appreciate it not being appealing just trying random things out. If you can't get hold of a description of the mainboard from its part number, ask around on PC repair forums. It's common sense.
Click to expand...

Yea my mainboard is pretty old and i am sure its even older than lot of members in pc forums ?
i just desoldered the parts and one still says 1k5 another doesnt show stable number but most of the time below 50 ohm
diode tester of multimeter confirms that its not a capacitor and due to beeps on both sides they are not a diode either
So
I should look for a replacment with 1k5 ohm or lower?
New pic:


- - - Updated - - -

pjmelect said:
You must remember that the highest voltage on a USB port is only 5V to have enough power to burn out those devices would require them to be of low resistance or a diode. For example a 1.5K resistor cannot burn out unless you fed a high voltage back into the USB port. For a resistor to burn out it would have to be less than 30 ohms or so. I would try and replace the burnt out components one at a time with fuse wire rated at a few hundred mA and see what happens.
Click to expand...

One of them is below 50 ohm another 1k5
One wired thing is that after damaging first port the current flow in second ports increased (i mesured it days before i lose all usb ports) i think it increased to about 2 amps( normal 0.7 amp ) can this explain the burnout in second ports?(with 1k5 ohm )
And if you see new pictures you can see one of contacts is melted so the smd itself might be okay?i mean my readings are currect and i just need resoldering?!?
and whats your sugesstion for resistor replacement . 30 ohm as you said or 1k5?
 

Both of these components are just ferrite beads. As you can see they are located on the power traces. Usually, these are 300 to 600 Ohms with 1A current rating.
 
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    d123

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mpfisher said:
Both of these components are just ferrite beads. As you can see they are located on the power traces. Usually, these are 300 to 600 Ohms with 1A current rating.
Click to expand...

Are you sure you didn't mean mOhms? For 300 Ohms @ 1A you would be dumping 300W through that ferrite bead. 0.3 Ohms at 1A seems much more reasonable.
 

300 ohms is an impedance of a ferrite bead usually specified at 100MHz. Its DC resistance will be much lower, somewhere around 0.3Ohm.
Hope this helps
 
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    ads-ee

    ads-ee

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mpfisher said:
300 ohms is an impedance of a ferrite bead usually specified at 100MHz. Its DC resistance will be much lower, somewhere around 0.3Ohm.
Hope this helps
Click to expand...

That makes sense now, didn't know that a bead is rated that way. Haven't done any board design for many decades. Last board I designed used 5V and was pushing 30 MHz clocks.
 

IF the USB ports are not working but the rest of the board is, it may be easier all round to simple add an USB interface card into an available slot.
 

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