rmmstn
Newbie level 6
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Hello ![Smile :) :)](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Currently, I am trying to create a network for matching 50ohms to 100ohms in CST. However, im having trouble while introducing the port impedances. My investigations show that discreet port would not be accurate as waveguide port. Therefore, I placed one waveguide port which is 50 ohm to the one port of the network, and I connected a lumped element(100ohm) which is from the ground plane to the top of the transmission line (so the whole thickness is covered actually) at the other port. However, it was not simulated since I am getting an error which is "the surface is not supported over the surface"(thats not the exact expression that cst gives btw.). If I connect a discreet port instead of the lumped element and adjust its impedance as 100ohm. Would the result I get be correct? In this case, I will have one waveguide and one discreet port. If not, how should I solve this matching problem? I really checked everything, but couldnt get an absolute answer.
Currently, I am trying to create a network for matching 50ohms to 100ohms in CST. However, im having trouble while introducing the port impedances. My investigations show that discreet port would not be accurate as waveguide port. Therefore, I placed one waveguide port which is 50 ohm to the one port of the network, and I connected a lumped element(100ohm) which is from the ground plane to the top of the transmission line (so the whole thickness is covered actually) at the other port. However, it was not simulated since I am getting an error which is "the surface is not supported over the surface"(thats not the exact expression that cst gives btw.). If I connect a discreet port instead of the lumped element and adjust its impedance as 100ohm. Would the result I get be correct? In this case, I will have one waveguide and one discreet port. If not, how should I solve this matching problem? I really checked everything, but couldnt get an absolute answer.