Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Register Log in

500 watt Invert-er Design .

Status
Not open for further replies.
Pulsetronics i meant is there any chopper (switching device ) both P-type and N-type enclosed in a ic . not SG3525 and SG3524.
 

Let me do a simple calculation for you , as your inverter is capable of delivering an active power of 500Watt , so I presume that you'll be using a 12V Battery at the input side.So if i calculate the Input current flowing in the primary winding of your ferrite transformer,it'll be 500/12 Ampere i.e 41.66 Ampere . If i presume the Rds =8milliohm of your switching device in ON state, i'll get a power discipation of 13.8 watt (using P= I*I*Rds) which is quite high , and will also need a BIG HEATSINK or Forced air cooling or both to discipate such amount of heat
so definetly you are not gonna get any IC which incorporates a switching device capable of switching a High Current (42 Ampere)..
 
Thanks, so use MOSFET instead of IC ?
 
Last edited:

You have to use an IC which is capable of generating pwm signals , now you have to drive the gate of the mosfets connected in push pull topology with those pwm signal.
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top