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HSPICE: how do I measure "Vout/(Vin1-Vin2)"?

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Nygen Patricia

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Hi all

This is a rather simple question. The circuit is a differential to single-ended. Meaning the gain is Vout/(Vin1-Vin2).


I have define:
*-----------------------------
*Indepedent voltage sources
* (I have Cmmom-mode of DC=1.5V with small signal *symmetric swing).
*-----------------------------
V+ Vin1 0 DC 1.5V AC 0.5 0 Sin(0 0.05 2kHz)
V- Vin2 0 DC 1.5V AC 0.5 180 Sin(0 -0.05 2kHz)



*printing out the gain
.print AC VDB(Vout,Vin1).

However, it should be Vout/(Vin1-Vin2). And I have trouble doing this. What can I do to make it happen?
 

Actually there is no need to give 180 degree phase shifted input to the second input.

you can set AC gain for one input and set 0 for second input

so no need to worry about vin1-vin2 as vin2 is zero..

Try this.

thanks
 
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