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[SOLVED] [Moved] how many instruction cycles?

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metals

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In assembly language for programming PIC, how many instruction cycles would this code take?

Code: 
hugo    movlw    0x14
          movwf    n
igen     decf      n,f
          bnz       igen
          nop
          nop
          rlncf      n,w
          movwf   portC
          nop
          return

I know that they all take 1 instruction cycle except for bnz which ned 1 or 2 and return that also need 2. But the answer is not 11/12 instruction cycles?
 

Re: how many instruction cycles?

Your loop counter is 20 (0x14) so it will take a'lot longer than 11/12 cycles.

Keith
 

Re: how many instruction cycles?

If you are using the MPLAB IDE, you can simulate the code for an exact count.

BigDog
 

Yes I am using MPLAB SIM, but somehow I can not really interpret the results.

I will post i pic, do you think this is the right answer? 57 cycles?

bbv.png


Your loop counter is 20 (0x14) so it will take a'lot longer than 11/12 cycles.
Click to expand...

I didn't think about that. But even if a count the cycles manually I only get 48, so which one is right? 48 or 57?

I counted like this:

Code: 
        movlw  0x14     <--- 1 x 1
        movf    n                <--- 1 x 1
igen   decf    n,f                 <----1 x 20
        bnz     igen             <----2 x 20
        nop                       <----1 x 1
        nop                       <----1 x 1
        rlncf    n,w               <----1 x 1
        movwf portC              <----1 x 1
        return                    <----1 x 2
 

Hi,

Use Sims Stopwatch -
 

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And now when I used stopwatch I got 88 instruction cycles :S
bbv22.jpg
 

Hi,

You do not seem to have used any breakpoints, so the program will have recorded all instructions, you should Zero the counter when you start your routine and stop it with a break point at the Return instruction.

Also not clear which chip you are using, your original code shows 18F instructions, your last entry has changed, could be 16F or 18F code ?
 

I used the "Step into" function so I could follow every instruction step by step. I think that is ok?
So I restarted the processor with F6 and then "Step into" line by line.

The chip I am using is a 16F877
 

Hi,

The Stopwatch I showed was run on a 18F because the code you gave used 18F instructions, RLFCF

If I run your latest code on a 16F877a then I agree with what you got.

Question for you - how long is 1 instruction cycle and where does it come from..?
 

movlw 0x14 <--- 1 x 1
movf n <--- 1 x 1

igen decf n,f <----1 x 20
btfss STATUS, Z <----1 x 19 + 1 x 2
goto igen <----2 x 19

; bnz igen <---- No such instruction on PIC16


nop <----1 x 1
nop <----1 x 1
rlcf n,w <----1 x 1
movwf portC <----1 x 1
return <----1 x 2

= 88
 

Hi,

The Stopwatch I showed was run on a 18F because the code you gave used 18F instructions, RLFCF

If I run your latest code on a 16F877a then I agree with what you got.

Question for you - how long is 1 instruction cycle and where does it come from..?
Click to expand...

Oh I didn't think about that. hmm this is a exercise I got from school, and since we usually use our 16F I assumed the code should be run on that.
But if RLFCF can't be used with 16F then it is probably supposed to be run on a 18F.

But still, when I do it manually I do something wrong because I get 48 cycles?



1 instruction cycle is 4 clock pulses, because it usually take 1 clock pulse to fetch the instruction, then to read it, to process at and the maybe write it out.
Was the answer right? :)
 

newfound said:
movlw 0x14 <--- 1 x 1
movf n <--- 1 x 1

igen decf n,f <----1 x 20
btfss STATUS, Z <----1 x 19 + 1 x 2
goto igen <----2 x 19

; bnz igen <---- No such instruction on PIC16


nop <----1 x 1
nop <----1 x 1
rlcf n,w <----1 x 1
movwf portC <----1 x 1
return <----1 x 2

= 88
Click to expand...


Hi,

Hmmm, missed the BNZ insruction and with the 16F877 it does not show a compile error ??

Here is the corrected code to replace the BNZ

Note that the Return instruction is invalid as no Call has been made for it to return to on completing the subroutine.
 

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newfound said:
movlw 0x14 <--- 1 x 1
movf n <--- 1 x 1

igen decf n,f <----1 x 20
btfss STATUS, Z <----1 x 19 + 1 x 2
goto igen <----2 x 19

; bnz igen <---- No such instruction on PIC16


nop <----1 x 1
nop <----1 x 1
rlcf n,w <----1 x 1
movwf portC <----1 x 1
return <----1 x 2

= 88
Click to expand...

So you replaced bnz with goto?
 

wp100 said:
Hi,

Hmmm, missed the BNZ insruction and with the 16F877 it does not show a compile error ??
Click to expand...

MPASM regards BNZ (and other conditional branches BZ. BNC, BC etc) as a built-in pseudo instruction and replaces it with the btfss STATUS, Z (or other conditional test for Z NC, C etc) and goto instructions.

- - - Updated - - -

metals said:
So you replaced bnz with goto?
Click to expand...

You didn't look very hard did you?
 
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    wp100

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newfound

Oh now I see what you did.


So with the chip I am using (16F) it is 88 cycles, but lets say we use the 18F chip then it is 75 cycles?
 

movlw 0x14 <--- 1 x 1
movf n <--- 1 x 1
igen decf n,f <----1 x 20
bnz igen <----2 x 19 + (1 x 1)
nop <----1 x 1
nop <----1 x 1
rlncf n,w <----1 x 1
movwf portC <----1 x 1
return <----1 x 2

= 67
 
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    metals

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newfound said:
movlw 0x14 <--- 1 x 1
movf n <--- 1 x 1
igen decf n,f <----1 x 20
bnz igen <----2 x 19 + (1 x 1)
nop <----1 x 1
nop <----1 x 1
rlncf n,w <----1 x 1
movwf portC <----1 x 1
return <----1 x 2

= 67
Click to expand...

Second last before return, you forgot a NOP, so total 68 cycles?
And btw I am wondering about BNZ igen. Why is there a + (1 x 1)?
 

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