Snitch
Junior Member level 3
In the datasheet of 18F452, it says,
"There is no priority bit associated with INT0. It is always a high priority interrupt source".
Does that mean, if we enable INT1 or INT2 or both, if INT0 occurs whenever any of those interrupt routines(INT1 or INT2) are being executed, their execution will be stopped at that point and INT0 interrupt routine will take place?
I need two interrupt routines and I need one of them to have higher priority so that it can interrupt the other one. If I just use INT0 and INT1(or INT2), without writing any code to set priority, would I be able to accomplish the task?
Thanks in advance.
"There is no priority bit associated with INT0. It is always a high priority interrupt source".
Does that mean, if we enable INT1 or INT2 or both, if INT0 occurs whenever any of those interrupt routines(INT1 or INT2) are being executed, their execution will be stopped at that point and INT0 interrupt routine will take place?
I need two interrupt routines and I need one of them to have higher priority so that it can interrupt the other one. If I just use INT0 and INT1(or INT2), without writing any code to set priority, would I be able to accomplish the task?
Thanks in advance.
