anhnha
Full Member level 6
Hi everyone,
Could you help me explain why UthD1 and UthD2 have phase reverse?
I read this equations from a book but it is not give me a detailed explaination about it.
UthD1 = Uth cos(ωth.t)
UthD2 = Uth cos(ωth.t + π )
UnsD1 = UnsD2 = Uns
i tg1 = I tg1 cos(ωns – ωth)t
i tg1 = -I tg2 cos[(ωns – ωth)t + π ] = -I tg2 cos(ωns – ωth)t
where UthD1 is the voltage of signal dropping in D1 diode
UthD2 is the voltage of signal dropping in D2 diode
Thanks a lot.
Could you help me explain why UthD1 and UthD2 have phase reverse?
I read this equations from a book but it is not give me a detailed explaination about it.
UthD1 = Uth cos(ωth.t)
UthD2 = Uth cos(ωth.t + π )
UnsD1 = UnsD2 = Uns
i tg1 = I tg1 cos(ωns – ωth)t
i tg1 = -I tg2 cos[(ωns – ωth)t + π ] = -I tg2 cos(ωns – ωth)t
where UthD1 is the voltage of signal dropping in D1 diode
UthD2 is the voltage of signal dropping in D2 diode
Thanks a lot.
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