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How to find gate counts?

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priyanka22

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Hello All,

I have generated netlist for my VHDL code now I want to find out gate counts for the VHDL code.
Kindly tell me how to calculate gate counts.

~With Regards
Priyanka Singh
 

it means I have to count it manually?
 

there is the simulation reslut.
未命名.JPG
 

yeah i know there is simulation results they don't tell us about Gate counts. I want the exact gate counts, how much all the primitive logic gates are involved in the design?
 

As TrickyDicky has said, you have to look at the compilation reports. If this code is intended for an FPGA, you have to build the coding using the vendor-specific tool chain, and the compilation report will tell you the amount of resources (i.e. LUTs, RAMs, etc) used by our code.

If the code is intended for an ASIC, then use Synopsys Design Compiler or similar, with the vendor libraries, and the compilation report will have the combinatorial and sequential gate counts, memory usage etc.

Without knowing which design technology is the target of your code, we can't be more specific.

r.b.
 

I am intended to design SoC using VHDL or ASIC design as well. Now what should be the procedure to find out the gate counts?
 

please tell which tool are you using for synthesis.........
then one can say which file to see for the area report.....
 

Hi,

".mrp" file contains the details of resource utilization of your device...it will be in your implementation directory you specified

Thanks
Manoj
 

Thank you for the help but as far as I know these details are for specific FPGA board but I want to count it independent of any board.

~With Regards
Priyanka Singh
 

Well i think you can get a good rough estimate from the report.by knowing how many registers are used and as how the LUTs are configured...if in case you just want to compare the gate counts of your vhdl codes

But, if you really want the exacy gate count, and your design is large i dont thing using a FPGA tool like xilinx will help.........

May be post the same question in the ASIC group, you might get the answer :)
 
Thank you once again!!! :)

~With Regards
Priyanka Singh
 

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