Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.
Actually , the chain I am talking about is inside the high speed transceiver eval board whose output are directly interfaced with the high speed receiver ADC pins.
That's why I can not test it through VNA.
So, I am asking for any approximate calc that I can done to estimate the phase delay...
Hello support team,
I have 2 different RF chains both can work with 2 GHz RF input but having different Balun, lumped components and matching network. So when I apply same input signal to both RF chains then how can I calculate the phase delay between the 2 chains due to non-identical...
Hello,
Thank you for your quick feedback.
Sorry for typo error in equation: What I am trying to say is that DAC output voltage for 14 bit resolution and 2.5 V ref. voltage = [2.5/16483] * digital input code
And my digital input is having this much of resolution and this range is fixed. so...
Hello,
I am planning to use DAC having the output range of 0 to 10 V with 14 bit resolution. ( if my DAC is having 2.5 V reference voltage)
so, my DAC output voltage will be =[ (2.5)/2^14-1 ]* digital data input
As my digital data input Hex value range is in between : 0x0033 to 0x0FE4 having...
Hello support team,
I have a requirement for 10 MHz clock generation (single ended -sine wave ) for my outdoor unit LNB through FPGA (zynq-7000 series). so is it possible to use below.
40 MHz TCXO interface to Clock capable pin >> Use of clocking wizard for the generation of 10 MHz >> assign...
For I^2+Q^2 , when I am applying -4.7 dBm RF input, below are the max and min value for the conseutive 1,31,072 samples.
Min value (I^2+Q^2) = 0.033015493
Max value (I^2+Q^2) = 0.033976138
Difference in measurement = 0.00096044
For I^2+Q^2 , when I am applying -40 dBm RF input using...
Hello support team,
I have implemented direct conversion method to generate I and Q samples from the RF frequency. and then I am using FPGA IP core to convert I and Q samples to amplitude measurement. I am taking digital samples of measured amplitude.
My input RF-ADC has 14 bit resolution and...
My input sampling rate to divider core is 61.44 MSPS and I am using Divider core with the same clock freq. of 61.44 MHz . that's why I am getting one output divided sample per clock cycle.
In a similar way, my moving average filter input sample rate is 20.48 MSPS and moving average core clock =...
I am looking for the total latency of the averaging algorithm because within 2 usec , my amplitude should measured. and I have calculated used IP cores latency which are 1.4 usec. so i need to figure out the moving averaging total latency(filter delay+ processing time/code)
for the filter...
Ok , so, latency formulla = (No of clock cycles)/clock
4/61.44 *10^6 = 65 nsec
1677212294
I have one doubt then,
If my input sample rate to any IP core is let's say 20 MSPS and If I use the IP core clock to higher let's say at 122.88 MHz. then it will possible to reduce the latency, right?
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.