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Ok, To make it a little more clearer,
The top capacitor gets charged during the +ve half cycle by the top diode. At this time, the bottom capacitor provides the current to the load via the diode across the top capacitor, thus providing the load with a constant current without ripple.
It would...
Re: Ground termination?
There! Brian has really made it clear. If an isolated power supply is used, the only thing connected to neutral is the transformer primary. Use it, it is simple and safe!
The ground of the circuit is just a reference and not really ground, ground, mother earth. :)
It refers to the minimum thickness ot the tracks used on a chip.
A 0.8 u technology would have far less density of circuitry as compared to a .35 or .16 u tecnology. Thus we could have a lot more circuitry on a .35 u chip, reducing the size and cost of the chip.
Here is how I look at it:
The output across the top capacitor would be 78*1.141 = 110V.
The path (+ve) is top diode, top capacitor and back to supply.
The output across the bottom capacitor would be 78*1.141 = 110V.
The path (-ve) is left diode, bottom capacitor and back to supply.
Hence the...
Re: Ground termination?
Hi eem2am !
So where do we differ???
Connect rectifier gnd to neutral and ain't all ckt grounds automatically shorted to neutral?
Now we do not want to connect neutral to Earth do we? The utilities would then have given us only 2 termianals!
Glad, I don't differ!
Re: Ground termination?
The Earth Pin is for protecting the person operating the device. If your device (box) is made of metal, it has to be grounded to the earth pin.
Now your circuits would have a ground and have to be connected to the neutral, I guess that is what you have shown. So connect...
I = (V1 - V2) / R, R = 0, Thus I = Infinity, The current would rise till the wire melts and they both will exist as 7 and 4 V!
In a real case. the current would flow from the 7V source to the 4V source and the weaker of the 2 would burn out or the wire would give way. Always connect a small...
The shunt is used to meausure current accurately.Its value is very small in micro ohms. The 2nd and 3rd pins are used to measure the current.The first pin is connected to the voltage circuit of the meter to avoid circulating currents of the power supply.
Re: Help needed
Connect a 10k from Vcc to ADC input.
Connect a 10k from ADC input to GND.
Let us say your micro works at 5V.
The ADC input is thus 2.5V without an input.
All + volts are above 2.5 and - volts are below 2.5 volts.
Thus you can measure +- 2.5 V :)
What is the supply voltage for the uC?
If it is 5, increase the lower resistor to get a value close to 5.Any value should then work.
Did you check the voltages with a multimeter with both combinations?
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